0
2.0kviews
Write a program to create a single link list and display the link list.
1 Answer
0
3views
# include <stdio.h> 
# include <stdlib.h> 
struct node 
{ 
    int data; 
struct node *link; 
}; 
struct node *insert(struct node *p, int n) 
{ 
struct node *temp; 
/* if the existing list is empty then insert a new node as the 
starting node */ 
if(p==NULL) 
{ 
p=(struct node *)malloc(sizeof(struct node)); /* creates new node 
data value passes 
as parameter */ 
if(p==NULL) 
{ 
printf("Error\n"); 
exit(0); 
} 
p-> data = n; 
p-> link = p; /* makes the pointer pointing to itself because it 
is a circular list*/ 
} 
else 
{ 
temp = p; 
/* traverses the existing list to get the pointer to the last node of 
it */ 
while (temp-> link != p) 
temp = temp-> link; 
temp-> link = (struct node *)malloc(sizeof(struct node)); /* 
creates new node using 
data value passes as 
parameter and puts its 
address in the link field 
of last node of the 
existing list*/ 
if(temp -> link == NULL) 
{ 
printf("Error\n"); 
exit(0); 
} 
temp = temp-> link; 
temp-> data = n; 
temp-> link = p; 
} 
return (p); 
} 
void printlist ( struct node *p ) 
{ 
struct node *temp; 
temp = p; 
printf("The data values in the list are\n"); 
if(p!= NULL) 
{ 
do 
{ 
printf("%d\t",temp->data); 
temp=temp->link; 
} while (temp!= p); 
} 
else 
printf("The list is empty\n"); 
} 
void main() 
{ 
int n; 
int x; 
struct node *start = NULL ; 
printf("Enter the nodes to be created \n"); 
scanf("%d",&n); 
while ( n -- > 0 ) 
{ 
printf( "Enter the data values to be placed in a node\n"); 
scanf("%d",&x); 
start = insert ( start, x ); 
} 
printf("The created list is\n"); 
printlist ( start ); 
}
Please log in to add an answer.