Consider the truss shown in figure.Given E = 210 GPa and cross section area A = 1 $cm^2$ for each element. Determine

1. Displacement at each node.

2. Stresses induced in each element.

3. Reaction at supports

Mumbai University > Mechanical Engineering > Sem 6 > Finite Element Analysis

Marks: 10M

Year: May 2015

$E = 210 GPa = 210 \times 10^3 N/mm^2\\ A = 1 cm^2 = 100 mm^2$

Sine rule,

$\frac{1000}{sin 105} = \frac{L_1}{sin 45} = \frac{L_2}{sin 30}\\ L_1 = 732.05 mm \\ L_2 = 517.638 mm$