Mumbai University > Electronics and Telecommunication Engineering > Sem 6 > Data Communication

Marks: 10 Marks

Year: Dec 2016

$L_{avg} = (0.4)2 + (0.19) \times 2 + (0.16) \times 2 + (0.15)3 + (0.1)3\\ L_{avg} 2.25 bit/symbol\\ H = 2.149 bit/symbol\\ \eta = \frac{H}{L} \times 100\\ \eta = \frac{2.149}{2.25} \times 100 \\ \eta = 95.5 \%$