A kaplan turbine runner is to be designed to develop 7357.5 Kw shaft power. The net available head is 5.5 m. Assume that the speed ratio is 2.09 and flow ratio is 0.68.

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written 8.7 years ago by

teamques10 ★ 70k

modified 3.7 years ago by

pedsangini276 • 4.8k

the overall efficiency is 60%. The diameter of the Boss is $\dfrac13$ of the diameter of the runner. Find the diameter of the runner, its speed, and its specific speed

Mumbai University > Electronics and telecommunication > Sem 7 > Applied Hydraulics

Marks: 08

Years: DEC 2014

applied hydraulics

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written 8.7 years ago by

teamques10 ★ 70k

• modified 8.7 years ago

Given :

Power P=7.57.5 Kw

Net head H = 5.5 m

Speed ratio = 2.09

Flow ratio = 0.68

Overall efficiency $N_0=60\% = 0.6$

Diameter of boss $=\dfrac 13$ of diameter of runner

$D_b= \dfrac 13 D_o$

Now speed ratio $= \dfrac {U_1}{\sqrt{2gH}} \\ \therefore U_1 = 2.09 \times \sqrt{2\times …

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