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Finite Element Analysis : Question Paper May 2016 - Mechanical Engineering (Semester 6) | Mumbai University (MU)

Finite Element Analysis - May 2016

Mechanical Engineering (Semester 6)

TOTAL MARKS: 80
TOTAL TIME: 3 HOURS
(1) Question 1 is compulsory.
(2) Attempt any three from the remaining questions.
(3) Assume data if required.
(4) Figures to the right indicate full marks.

Write the short note on (ANY FIVE)

1(a) Pre-Processing, Processing and Post-Processing in FEA.(4 marks) 1(b) Sub parametric, Iso-parametric and super parametric element in FEA.(4 marks) 1(c) Geometric and Forced boundary condition(4 marks) 1(d) Advantages and limitations of the FEM.(4 marks) 1(e) Write element matrix equation in the following fields. Explain each term properly.
(i) ID steady state, heat transfer by conduction.
(ii) ID, steady state flow of fluid in a pipe
(4 marks)
1(f) Sources of Error in FEA.(4 marks) 2(a) Solve the following differential equation using Gelerkin Method. $$-\dfrac{d}{dx}\left [ (x-1)\dfrac{du}{dx} \right ]=x^2\ ;3\leq x \leq 5$$
Boundary conditions: u(5)=10 and u'(3)=5
Compare the answers with exact solution at x=4 and 5.
(10 marks)
2(b) Compute the temperature at point P(2.5, 2.5) using natural coordinates system for quadrilateral element shown in the figure. Take: T1=100°C, T2=60°C, T3=50°C, T4=90°C

(10 marks) 3(a) A copper fin of diameter 20mm, length 60mm bad thermal conductivity is 100 W/m0 C and is exposed to ambient air at 30°C with a heat transfer coefficient 25 W/m2 0 C. If one end of the fin is maintained at temperature 500°C and other end is at 200°C. Solve the following differential equation for obtaining the temperature distribution over the length of a fin $$kA.\dfrac{d^2\theta}{dx^2}-hp\theta=0$$
θ= Temperature difference=Tx-Ta
Use Rayleigh-Ritz mathod, mapped over general element, taking Lagrange's linear shape functions and two linear elements.
Write all the steps clearly. Compare your answer with exact at x=20,40 mm
(15 marks)
3(b) What do you mean by consistent and lumped mass matrices? Derive the same for linear bar element.(5 marks) 4(a) Find the natural frequency of axial vibration of a bar having cross sectional area as 30 × 14-4 m2, 1 m length with left end fixed. Take E=2 × 1011 N/m2. Density of the material is 7800 Kg/m3. Take two linear elements.(10 marks) 4(b) Analyze the truss completely for displacement and stress as shown in figure.
Take: E = 2× 105 Mpa.

 ELEMENT AREA, mm2 LENGTH, m 1 20 6 2 20 3

(10 marks) 5(a) Using FEM, analyze the taper bar as shown in figure. The cross sectional area to the left and right to is equal to 80 mm2 and 20 mm2. Take length of bar is equal to 60 mm, Take E=210 Gpa.

(10 marks)
5(b) Evaluate the shape function and prove its property, for triangular element as shown in figure. Also sketch the variation of shape function for each node.

(10 marks)
6(a) Determine the displacement at nodes by using the principal of minimum potential energy and find the support reaction.
Use, k1 = 100 N/mm, k2 = 300 N/mm,
k3 = 150 N/mm, k4 = 300 N/mm.

(10 marks)
6(b) A CST element has nodal coordinates (10,10), (70,35) and (75,25) for nodes 1,2 and 3 respectively. The element is 2 mm thick and is of material with properties E = 70 Gpa. Poission's ratio is 0.3. After applying the load to the element the nodal deformation were found to be u1 = 0.01 mm, v1 = -0.04 mm, u2 = 0.03 mm, v2 = 0.02 mm, u3 = -0.02 mm, v3 = -0.04 mm. Determine the strains ex, ey, exy and corresponding element stresses.(10 marks)

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