Mumbai University > EXTC > Sem 8 > Satellite Communication and Networks

Marks: 10M

1.Brad ford UK station (54°N,2°W)

2.Blacksburg USA (37°N, 80°W)

Given:

Longitude of satellite $(ϕ_s )$=$35^0 W$

brad ford UK station (54°N,2°W)

Latitude of earth station $(θ_e)$=$(54)^0N$

Longitude of earth station $(ϕ_e)$=$2^0W$

To find: Look Angles=?

Slant Range=?

Solution:

Hence

$θ_e$=$54^0$

$ϕ_e$=$-2^0$

$ϕ_s$=$-35^0$

$ϕ_es$=$ϕ_e-ϕ_s$

=-2+35

$∴ϕ_es=33^0 $ i.e earth station is to the east of subsatellite point

To calculate Azimuth …