Mumbai University > Electronics Engineering > Sem 4 > Discrete Electronic Circuits

Marks: 10M

Given:

$I_{DSS} = 7mA$

Vp = -2.5V

We know that,

$I_{DS}=I_{DSS}(1-\frac{V_{GS}}{V_{p}})^2$

$I_{DS}=7m(1+\frac{VGS}{2.5})^2$-----------(1)

Put different values of VGS and obtain IDS in equation (1),

$V_{GS} (V)$	$I_{DS}(mA)$
0	7
-0.5	4.48
-1	2.52
-1.5	1.12
-2	0.28
-2.5	0

Figure 1 shows the Graph of $V_{GS}V_s I_{DS}$

Apply KVL from R2 …