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Determine optimum cost & estimated as Rs. 5000/- day.

Mumbai University > Civil Engineering > SEM 8 > Construction Management

Marks: 12M

The utility data for activities of a project is indicated below. Determine optimum cost & estimated as Rs. 5000/- day.

Activity Normal Duration (days) Normal Cost (Rs.) Crash Duration (days) Crash Cost (Rs.)
1-2 6 7000 3 14500
1-3 8 4000 5 8500
2-3 4 6000 1 9000
2-4 5 8000 3 15000
3-4 5 5000 3 11000
4-5 7 8000 4 15000
1 Answer
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Activity Normal Duration (days) Normal Cost (Rs.) Crash Duration (days) Crash Cost (Rs.) Cost Slope
1-2 6 7000 3 14500 2500
1-3 8 4000 5 8500 1500
2-3 4 6000 1 9000 1000
2-4 5 8000 3 15000 3500
3-4 5 5000 3 11000 3000
4-5 7 8000 4 15000 2333.33
38000 73000

$\text{Cost Slope} = \frac{\text{Crash Cost - Normal Cost}}{\text{Normal Time - Crash Time}}$

Stage 1 : - Normal Time

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Critical path = 1-2-3-4-5

Project duration = 22 days

Stage 2 :- Crash Time

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Critical path = 1-3-4-5

Project duration = 12 days

Stage 3 :- Stage 1+ Crash C by 2 days and Crash E by 1 day

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Critical path =1-2-3-4-5 = 1-3-4-5

Project duration = 19 days

Stage 4 :- Stage 3 +Crash A by 1 day & Crash B by 1 day

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Critical path = 1-2-3-4-5 = 1-3-4-5

Project duration = 18 days

Stage Description Duration Direct Indirect Addition Total
1 All Normal 22 38000 22,5000=11000 - 148000/-
2 All Crash 12 73000 12,5000=60000 - 133000/-
3 Stage 1+ Crash C by 2 days and Crash E by 1 day 19 38000 19,5000=95000 2,1000+1,3000 138000/-
4 Stage 3 +Crash A by 1 day & Crash B by 1 day 18 38000 18,5000=90000 5000+1,2500+1,2500 137000/-

∴ Optimum cost = Rs. 137000/-

Optimum duration = 18 days

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