Determine optimum time cost combination.

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written 8.1 years ago by

teamques10 ★ 70k

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$\text{Cost Slope} = \frac{\text{Crash Cost - Normal Cost}}{Normal Time - Crash Time}$

Stage 1 : - All Normal

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Critical path = 10-30-60-70

Project duration = 15 days

Stage 2 : - All Crash

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Critical path = 10-30-60-70

Project duration = 8 days

Stage 3 : - All Normal + Crash E by 3 days

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Critical path = 10-30-60-70 / D-E-F

Project duration = 12 days

Stage 4 : - Stage 3 + Crash D by 2 days

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Critical path = 10-20-50-70 / A-B-G

10-30-60-70 / D-E-F

Stage	Description	Duration	Direct	Indirect	Addition	Total
1	All Normal	15	47000	$15 \times 1000 = 15000$	-	62000
2	All Crash	8	76000	$8 \times 1000 = 8000$	-	84000
3	All Normal + Crash E by 3 days	12	47000	$12 \times 1000 = 12000$	$3 \times 1000 = 3000$	62000
4	Stage 3 + Crash D by 2 days	10	47000	$10 \times 1000 = 10000$	$3000 + 2 \times 1500$	63000

Optimum cost = Rs. 62000/-

Optimum duration = 12 days

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