Following are the details of a small civil engineering projects.

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written 8.3 years ago by

teamques10 ★ 70k

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$\text{Cost Slope} = \frac{\text{Crash Cost-Normal Cost}}{\text{Normal Time-Crash Time}}$

Stage 1 :- All Normal

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Critical path = 10-20-30-50-70-80-90 i.e. (P-Q-T-V-X)

Project duration = 29 days

Stage 2 :- All Crash

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All Crash

Project duration = 20 days

Stage 3 :- Stage 1 + Crash Q by 1 day

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All Crash

Project duration = 28 days

Stage 4 :- Stage 3 + Crash T by 1 day + Crash U by 1 day

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All critical

Project duration = 27 days

Stage	Description	Duration	Direct Cost	Addition Cost	Total cost
1	All Normal	29	68000	-	126000
2	All Crash	20	98000	-	138000
3	Stage 1 + Crash Q by 1 day	28	68000		125500
4	Stage 3 + Crash T by 1 day + Crash U by 1 day	27	68000		126666.66

Optimum cost = Rs. 125500/-

Optimum duration = 28 days

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