Subject :- Applied Physics 2.

Topic :- Laser.

Difficulty :- Low.

In static electric fields the work done involved in moving a test charge around a closed path is equal to zero. Such fields are called conservative fields. In this case,

$$\oint_C\vec{E}.\vec{dl}=0$$

This is integral form of faradays law for static electric field. Using stoke’s theorem this can be written as

$$\oint_C\vec{E}.\vec{dl}=\oint_S(\vec{\nabla}\times\vec{E}).\vec{ds}=0$$

Hence, $\vec{\nabla}\times\vec{E}=0$

This is differential or point form of faraday’s law for static electric field.