Derive an expression for deflection of helical spring of circular wire.

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written 7.6 years ago by

bhaveshkumarn.pasi • 530

• modified 7.6 years ago

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$D=Mean \hspace{1mm} diameter \hspace{1mm} of \hspace{1mm}the\hspace{1mm} spring \hspace{1mm}coil $

$d=diameter \hspace{1mm}of \hspace{1mm}the\hspace{1mm} spring \hspace{1mm}wire$

$n=Number \hspace{1mm} of\hspace{1mm} active\hspace{1mm} coils$

$G=modulus\hspace{1mm} of \hspace{1mm}rigidity\hspace{1mm} for\hspace{1mm} the \hspace{1mm}spring\hspace{1mm} material$

$W=axial\hspace{1mm} load\hspace{1mm} on \hspace{1mm}the\hspace{1mm} spring $

$C=Spring\hspace{1mm} index=D/d$

$p=pitch\hspace{1mm} of\hspace{1mm} the\hspace{1mm} coils$

$\delta=deflection \hspace{1mm}of\hspace{1mm} the\hspace{1mm} spring \hspace{1mm}as\hspace{1mm} a \hspace{1mm}result\hspace{1mm} of\hspace{1mm} an \hspace{1mm}axial \hspace{1mm}load\hspace{1mm} W$ …

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