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Fit a Binomial distribution

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Fit a Binomial distribution

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written 3.6 years ago by |

Solution:

$\bar{X}= \frac {\sum f_i x_i}{N} =\frac{0+18+56+36+28+30+24}{80}=\frac{192}{80}=2.4$

p=$\frac{\bar x}{n}=\frac{2.4}{6}=0.4 \therefore q=1-p=1-0.4=0.6$

The Binomial distribution is p(X=x) $^nC_x p^x q^{n-x} = ^6C_x (0.4)^x (0.6)^{6-x}$ i.e.

x : 0 1 2 3 4 5 6

f : 4 15 25 22 11 3 0

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