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Newtons rings are observed in the reflected light of $\lambda = 6000 \mathring{A}$ Find the thickness of the air film corresponding to the $10^{th}$ dark ring.

written 7.9 years ago by teamques10 ★ 70k

•   modified 3.9 years ago

Subject: Applied Physics 2

Topic: Interference And Diffraction

Difficulty: Medium

engineering physics

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written 7.8 years ago by teamques10 ★ 70k

λ = 6000 x10$^{-8}$ cm, n=10

For dark ring , 2μt= nλ

Thickness $ t= \frac{nλ}{2μ}$

For air film μ=1,

$\therefore$ Thickness $ t= \frac{nλ}{2} = \frac{10 \times 6000 \times 10^{-8}}{2} = 30000 \ AU$

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