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In the Newtons ring experiment, the diameter of the $10^{th}$ dark ring changes from 1.4 to 1.27 cm when a liquid is introduced between the lens & the plate. Calculate RI of liquid.
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Solution:

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The radii of Newton's light ring with a constant radius of curvature of the lens is given by

$$ r_{k}=\sqrt{\frac{(k-0.5) \lambda R}{n}} $$

where,

$r=$ radius of the ring

$k=$ newton's constant

$\lambda=$ wavelength of a ray

$\mathrm{R}=$ radius of curvature

$\mathrm{n}=$ refractive index

Now, the radius of the …

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