Light of $\lambda$ = 5000 $\mathring{A}$ falls normally on a single slit of width 0.3 mm. Calculate the total angular as well as linear width of the central maximum obtained on the screen placed at 1 m from the slits.

Subject: Applied Physics 2

Topic: Interference And Diffraction

Difficulty: Medium

λ = 5000 x 10$^{-8}$ cm, a= 3 x10$^{-2}$ cm,first minimum so n=1

Distance of screen from the slit 100 cm = f = 100 cm

a sinθ = nλ

Total angular width of the central maximum is twice the angle made by the first minimum with the normal to …