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Find the maximum value of RP a grating 3 cm wide & having 7000 lines/cm can have if a light of $\lambda$ = 5000 $\mathring{A}$ is used.

Subject: Applied Physics 2

Topic: Interference And Diffraction

Difficulty: Medium

1 Answer
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Width W = 3 cm, N = 7000 lines/cm, λ = 5000 A°

grating element $ (a+b) = \frac{1}{N} = \frac{1}{7000} $

RP is maximum when n is maximum

N is maximum when sin θ =1

(a+b) sin θ = n λ

$ n_{max} = \frac{1}{Nλ} = \frac{1}{ 7000 \times …

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