Determine the ratio of population of higher to lower energy level in an atom at RT under thermal equilibrium if the energy difference between the 2 levels corresponds to $\lambda$ = 500 nm.

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written 7.9 years ago by

neeta.vanage • 880

modified 3.9 years ago by

pedsangini276 • 4.8k

Subject :- Applied Physics 2.

Topic :- Lasers.

Difficulty :- Medium.

engineering physics

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1 Answer

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written 7.8 years ago by

neeta.vanage • 880

modified 7.8 years ago by

saurabhsingh • 40

$(E_2 - E_1 ) = hν = hc/λ \\ $

$h= 6.634 * 10^{-32} \\ $

$c = 3 * 10^{8} \\ $

$ λ = 500*10^{-9} m \\ $

$ K = 1.38 * 10^{-23} J/K \\ $

$ T = 27 +273 =300 K \\ $

$ hc/λ = 6.634*10^{-34} * 3*10^{8} / 500 * 10^{-9} = 3.98*10^{-19} \\ $

$ KT =1.38 *10^{-23} * 300 = 4.14 *10^{-21} \\ $

$ N_2 / N_1 = 1.7834*10^{-42} \\ $

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