An optical fiber has NA = 0.25 & cladding RI = 1.55. Determine its acceptance angle when this fiber is immersed in water having RI 1.33. Also calculate its core RI.

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written 7.9 years ago by

neeta.vanage • 880

modified 3.9 years ago by

pedsangini276 • 4.8k

Subject: Applied Physics 2

Topic: Fiber Optics

Difficulty: Medium

engineering physics

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1 Answer

1.5kviews

written 7.8 years ago by

neeta.vanage • 880

modified 7.7 years ago by

yashbeer ★ 11k

$ NA =0.25 $

$ n_2 = 1.55 $

$n_o = 1.33 $

$n_1 = ? $

$i_m = ? $

$ NA = n_1^2 - n_2^2 $

$(0.25)^2 = n_1^2 - (1.55)^2 $

$0.0625 = n_1^2 - 2.4025 $

$⸫ n_1^2 = 2.465 $

$⸫ n_1 = 1.57 $ …

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