Subject: Applied Physics 2

Topic: Motion Of Charged Paqrticle In Electric And Magnetic Field

Difficulty: Medium

A CRT has anode voltage 1.6 kV & parallel deflection plates are 1.8 cm long & 4.2 mm apart. The screen is at 2.8 cm from centre of deflecting plates. Find the input voltage required to deflect the beam by 1.5 cm.

$$ $$ $ V_A = 1.6*10^3 V \\ l = 1.8 cm \\ d = 0.42 cm \\ D = 2.8 cm \\ V =? \\ Y=1.5 cm \\ $

$Y = (D l V)/(2 dVA ) \\ 1.5 =(2.8*1.8*V) / (2*0.42*600 ) \\ ⸫ V = 400 V \\ $