Electrons accelerated by a potential of 400V encounter an equipotential boundary making an angle of $50^0$ with the normal & get refracted at an angle of $40^0$. Find the potential difference between the two regions.

Subject: Applied Physics 2

Topic: Motion Of Charged Paqrticle In Electric And Magnetic Field

Difficulty: Medium

: $$ $$ $ (sin⁡θ_1) / (sinθ_2 ) = √(V_2/V_1 ) \\ sin⁡50/sin⁡40 = √(V_2/400) \\ 0.766/0.642 =√(V_2/400) \\ 1.4235 * 400 = V_2 \\ V_2 = 569.43 \\ \text{Potential difference between two region }569.43 – 400 = 169.4 V \\ $