With the neat flowchart/algorithm write a program in 8086 assembly to arrange a set of ten 8-bits numbers initialized in data segment in ascending order

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written 7.0 years ago by

omkarthopate2111 • 0

Flowchart:

Algorithm:

Initialize the data segment.
Initialize the number of elements counter.
Initialize the pointer and number of comparisons counter.
Compare the elements. If first element < second element go to step VI else go to step V.
Swap the elements.
Increment the pointer. Decrement the comparison counter.
Is count = 0? If yes, go to step VIII else go to step IV.
Decrement the number of elements counter.
Is count = 0? If yes, go to step X else go to step III.
Stop.

Label	Instruction	Comment
	.model small	;
	.stack 100	Initialize stack segment
	.data	Initialize the data segment
	num dw 0102H, 0154H, 0070H, 0005H	Initialize data
	count dw 04	Initialize counter
	.code	Initialize code segment
	mov ax, @data	Initialize data section
	mov ds, ax
	mov dx, count	Initialize the number of elements counter
	dec dx	Number of comparisons is one less than the number of elements
loop2:	lea si, num	Initialize the pointer
	mov cx, dx	CX number of comparisons required
loop1:	mov ax, [si]	Load a data
	cmp ax, [si + 2]	Compare it with next number
	jc next	If previous number < = this number go to next
	xchg [si + 2], ax	Swap if not sorted
	mov [si], ax	Insert in new position
next:	inc si	Increment si
	inc si
	loop loop1	Decrement comparison counter and repeat if not zero
	dec dx	Decrement number of elements counter
	jnz loop2	Repeat if not zero
	mov ah, 4ch	Termination of the program
	int 21h
	end start

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