A kite weighing 0.8kg effective area= $0.8m^2$. It is maintained in the air at an angle of $10^0$ to the horizontal. The string attached to the kite makes an angle of $45^0$ to the horizontal and at this position, the value of Cd = 0.6, CL = 0.8 respectively. Find the speed of the wind and the tension in the string.$ Take \rho = 1.25 kg/m^3$.

Solution :

Given :

1. Weight of kite, $W=0.8\mathrm{~kgf} = 0.8 \times 9.81 = 7.848 \mathrm{~N}$

2. Angle made by kite with horizontal $=10^{\circ}$

3. Angle made by string with horizontal $ = 45 ^ { \circ }$

4. $ C_{D}=0.6 $

5. $C_{L}=0.8$

6. Density of air, $ \rho=1.25 \mathrm{~kg} / \mathrm{m}^{3}$

Let the speed …