The specific energy for 5m wide rectangular channel is 4Nm/N. If rate of flow of water is through the channel is $20m^3/s.$ Determine the alternate depth of flow.

4.5kviews

written 7.9 years ago by

mitali.poojari1908 • 400

modified 3.7 years ago by

Krishna_Agrawal • 2.7k

applied hydraulics

ADD COMMENT EDIT

1 Answer

552views

written 3.7 years ago by

Krishna_Agrawal • 2.7k

Given,

$b = 5m$

$E = 4Nm/N = 4m$

$Q = 20 m^3/s$

$E= 4$

$E = h + \frac{V^2}{2g}$

$V= Discharge/area =Q/b\ \times\ h= 20 / 5 \times\ h$

$E = h + \frac{V^2}{2g} = h + (4/h)^2 \times 1/2 g$

$E = h + \frac{8}{g \times h^2}$

$4 …

Create a free account to keep reading this post.

and 3 others joined a min ago.

ADD COMMENT EDIT

Please log in to add an answer.