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Discuss LL fault in detail
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| written 3.6 years ago by |

Current equation:
Phase Current relation:
$$ I_{b}=I_{f}=-I_{c} \quad I_{a}=0 $$ $\frac{\text { Symmetrical Current relation: }}{I_{b}+I_{c}=0}$ $$ \begin{aligned} &I_{b}+I_{c}=0 \\ &I_{a 0}+a^{2} I_{a 1}+a I_{a 2}+I_{a 0}+a I_{a 1}+a^{2} I_{a 2}=0 \\ &2 I_{a 0}+\left(a^{2}+a\right) I_{a 1}+\left(a^{2}+a\right) I_{a 2}=0 \\ &2 I_{a 0}-I_{a 1}-I_{a 2}=0 \quad …