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The line AB 60 mm long is inclined at an angle $25^0 $to the HP and $40^0$ to the VP. Its end A is 10 mm above the HP and 20 mm in front of the VP.

The line AB 60 mm long is inclined at an angle $25^0$ to the HP and $40^0$to the VP. Its end A is 10 mm above the HP and 20 mm in front of the VP. Draw the projections of line AB. Assume both ends A and B are in I quadrant.

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Notation

(TL) = a’b’1 (in FV) = ab2 (in TV)

A is above HP = a’ (↑)

A is below HP = a’ (↓)

A is in front of VP = a (→)

A is in behind VP = a (←)

Front View (FV) = a’b’

Top View (TV) = …

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