0
56kviews
A triangular prism base 40 mm long and height of axis 65 mm has one of its base edge in HP and inclined at $40^0$ to the VP. Draw projections when the axis is inclined at $45^0$to HP
2
10kviews

Given Data

Side of prism = 40 mm

Axis length = 65 mm

Resting on HP, Base edge inclined to VP = 40°

Axis inclined to HP = 45°

Procedure -

1. Draw XY line.

2. A prism is resting on HP, so triangle will be seen in TV and rectangle in FV.

3. Draw TV as a triangleone side of base inclined 40° to XY line.

4. Draw a line incline at 40° to XY line. Taking any arbitrary point at some convenient distance below XY line say 3 mark point 2 at 40 mm (side of prism).

5. As the triangle is equilateral triangle other with help of compass and complete the TV.

6. Name the triangle 1 2 3 .

7. Take the projections of all corners into FV.

8. Complete the FV taking axis length 65 mm.

9. Name the FV on both top base as well as bottom base 1’ 2’ 3’.

Stage 2

1. As axis is inclined at 45° to XY line the line 1’2’ will be at 45° to XY line.

2. So first mark point 2’ at some convenient distance on XY line. Then draw line 2’1’ at an angle of 45°, so that the axis will be inclined at 45°.

3. Using compass mark points 3’on the line 2’1’.

4. Complete the FV in inclined position using compass.

5. Take the projections of all 6 points 1’2’3’ from both the bases in TV.

6. Take the horizontal projections of triangle corners towards right side.

7. Intersection of 1 and 1’ will give point 1, Intersection of 2 and 2’ will give point 2, Intersection of 3 and 3’ will give point 3, for both the bases.

8. Side of bottom base 2’3’ will not be visible in TV, also vertical edge 2’2’ also not visible. Draw this lines as hidden lines.