0
4.0kviews
A semicircular symmetrical three hinged arch has a span of 20m.The arch sustains a load of 45 KN/m on the left half of the span.

Determine

1) The horizontal thrust

2) The moment,radial shear and normal thrust at a section 6m from the left hand support

3) Draw B.M.D


1 Answer
0
96views

enter image description here

Note: Since the arch is symmetrical h=10m


1) $Rx^n$ and horizontal thrust

$\sum M_A = 0 (\circlearrowleft+ve)$

$45 \times 10 \times \frac{10}{2} - V_B \times 20 = 0$

$\boxed{V_B = 112.5 KN}$

$\sum F_y = 0 (\uparrow +ve)$

$V_A - 45 \times 10 + 112.5 = 0$

$\boxed{V-A = 337.5 …

Create a free account to keep reading this post.

and 5 others joined a min ago.

Please log in to add an answer.