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A leather is required to transmit 7.5 kw from a pulley 1.2 m in diameter, running at 250 rpm.

The angle embraced is 165 deg and the coefficient of friction between the belt and the pulley is 0.3. If the safe working stress for the leather belt is 1.5 MPa, density of leather 1Mg/m^3 and thickness of belt 10 mm, determine the width of the belt taking centrifugal tension into account.


Subject: Kinematics of Machinery

Topic: Belts, Chains and Brakes

Difficulty: Medium

1 Answer
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P= 7.5 kw =7500 w; d =1.2 m; N =250rpm. ;$\theta$ =165$^{\circ}$ =165 ×($\pi$/180) =2.88 rad; $\mu$ =0.3 ; $\sigma$ =1.5 M$P_{a}$ = 1.5×10$^{6}$ N/$m^{2}$ ; $\rho$ = 1 Mg//$m^{3}$ =1 ×10/$^{6}$ g//$m^{3}$ =1000 kg//$m^{3}$ ;t = 10 mm =0.01 m.

​Let $b$ =width of the belt in meters, $T_{1} …

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