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Solve $(D^4+8D^2+16)y=sin^2x$ .
1 Answer
written 6.2 years ago by | • modified 6.1 years ago |
$ \text{ The Auxillary equation is } \\ $
$ D^4 + 8D^2 +16 = 0 \\ $
$ (D^2 + 4)^2 = 0 \\ $
$D=\pm 2i, \pm2i \\ $
$ \text{ C.F. is } y = (c_1 + c_2x)cos2x + (c_3 +c_4x)sin2x\\ $
$ \text{P.I = } \frac{1}{D^4 …