| written 8.0 years ago by | • modified 8.0 years ago |
Put,
$ax^{1/n}=t \hspace{0.3cm}=\gt\hspace{0.3cm} x^{1/n}=t/a \hspace{0.3cm}=\gt x=(\frac{t}{a})^n $
$dx =n(\frac{t}{a})^{n-1}*\frac{1}{a}dt$
$\int_{0}^{\infty} cos\,t \frac{n}{a^n}t^{n-1}dt =\frac{n}{a^n}\int_{0}^{\infty}cos\,t \,t^{n-1}dt$
R.P
$\frac{n}{a^n}\int_{0}^{\infty}e^{-it}\,t^{n-1}dt$
Put,
$it=u \hspace{0.3cm}=\gt\hspace{0.3cm}idt=du $
R.P,
$\frac{n}{a^n} \int_{0}^{\infty} e^{-u} (\frac{u}{i})^{n-1} \frac{du}{i}=\frac{n}{a^n\,i^n} \int_{0}^{\infty} e^{-u} u^{n-1} du $
$\hspace{4.5cm}= \frac{n}{a^n\,i^n}\sqrt{n}$
R.P
$\frac{\sqrt{n}+1}{a^n} i^{-n}$
R.P
$\frac{\sqrt{n}+1}{a^n} (cos\,\frac{\pi}{2}+i\,sin\,\frac{\pi}{2})^{-n}$
R.P,
$\frac{\sqrt{n}+1}{a^n} (cos\,n\frac{\pi}{2}-i\,sin\,n\frac{\pi}{2})\hspace{0.3cm}$
(Demoivre's Theoram)
$\frac{\sqrt{n}+1}{a^n} \, cos\,n\frac{\pi}{2}$

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