| written 7.8 years ago by | • modified 3.9 years ago |
Subject: Structural Analysis 1
Topic: Deflection of Beams using Energy Method
Difficulty: High

| written 7.8 years ago by | • modified 3.9 years ago |
Subject: Structural Analysis 1
Topic: Deflection of Beams using Energy Method
Difficulty: High

| written 7.8 years ago by | • modified 7.6 years ago |
1. Reaction
$\begin{align} &\sum M_A=0\ (\circlearrowright+ve) \\& 10\times3\times\frac{3}{2}+15\times3-V_D\times5=0 \\& \boxed{V_D=18\ kN\ (\uparrow)} \\ \\& \sum F_Y=0\ (\uparrow+ve) \\&V_A-15+18=0 \\& V_A=-3\ kN \\& \boxed{V_A=-3\ kN\ (\downarrow)} \\ \\& \sum F_X=0\ (\rightarrow+ve) \\&H_A=10\times3=0 \\&H_A=-30\ kN \\& \boxed{H_A=-30\ kN\ (\leftarrow)} \end{align}$

2. Table: [$\circlearrowright|\circlearrowleft+ve$]
| Region | origin | Limit | Mu | Mu(H) | EI |
|---|---|---|---|---|---|
| AB | A | 0-3 … |