0
2.2kviews
A simple supported beam shown in fig is subject to a set of 4 concentrated load which moves from left to right, determine a.Absolute max shear force (S.F) b.Absolute max bending moment (B.M)
1 Answer
written 6.2 years ago by | • modified 6.1 years ago |
1)Absolute Max +ve Shear
$ SF= 80 \times 1+60 \times \frac{16}{18}+80 \times \frac{14}{18}+100 \times \frac{11}{18}$
$SF= 256.67KN$
2) Absolute Max -ve Shear
$SF= -[80 \times \frac{11}{18}+60 \times \frac{13}{18}+80 \times \frac{15}{18}+100 \times 1$
$SF=-[258.88]KN$
3) Absolute Max B.M.
$By \hspace{1mm} Varignon's \hspace{1mm} theorem$
$80 \times 3+60 \times 5+80 \times 7=320 \times …