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A simple supported beam shown in fig is subject to a set of 4 concentrated load which moves from left to right, determine a.Absolute max shear force (S.F) b.Absolute max bending moment (B.M)

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1)Absolute Max +ve Shear

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$ SF= 80 \times 1+60 \times \frac{16}{18}+80 \times \frac{14}{18}+100 \times \frac{11}{18}$

$SF= 256.67KN$


2) Absolute Max -ve Shear

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$SF= -[80 \times \frac{11}{18}+60 \times \frac{13}{18}+80 \times \frac{15}{18}+100 \times 1$

$SF=-[258.88]KN$


3) Absolute Max B.M.

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$By \hspace{1mm} Varignon's \hspace{1mm} theorem$

$80 \times 3+60 \times 5+80 \times 7=320 \times …

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