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Show that for the capacitor in parallel as shown in figure the capacitance is $C_{eq}=\frac{\epsilon_{0}\epsilon_{r1}A_{1}}{d}+\frac{\epsilon_{0}\epsilon_{r2}A_{2}}{d}=C_{1}+C_{2}$
written 6.4 years ago by
govindkedar
• 280
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modified 2.6 years ago
by
sagarkolekar
★ 11k
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