Question (contd.) find out the stress produced at extreme fibre of the column section. Take E=200GPa

Given data:

$ D= 300mm\\ d=220mm\\ l=4m\\ t=40mm\\ Load(P)=100\ kN\\ eccentricity\ e=40\ mm\\ E=200GPa=2\times10^5MPa$

To find: Extreme stress

For a hollow circular column

Area of the column,

$A=\frac{\pi}{4}(D^2-d^2)=\frac{\pi}{4}(300^2-220^2)=32672.56\ mm^2$

Moment of inertai of the column section

$ I=\frac{\pi}{64}(D^4=d^4)=\frac{\pi}{64}(300^4-220^4)=282.62\times10^6mm$

Section Modulus (z) =$\frac{I}{y}=\frac{282.62\times10^6}{150}=1.884\times10^6mm^3$

Since the column is pinned at both ends …