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Draw the stress distribution diagram at the base of a column of hollow circular section with external diameter 200mm and thickness 20mm. The column is 6m long having both ends fixed. It ...(contd.)

Question (contd.) carries a load of 80 kN ata n eccentricity of 25mm from the column axis. Take E = 200GPa

Subject : Structural Analysis 1

Topic : Struts

Difficulty : High

1 Answer
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Given data:

$ D=200mm\\ d=160mm\\ L=6m \\ t=20mm \\ P=80\ kN\\ eccentricity\ e=25mm\\ E=200GPa=2\times10^5MPa$

To find: $\underline{Extreme Stress}$


$Area\ of\ column,\ A=\frac{\pi}{4}(D^2-d^2)\\ = \frac{\pi}{4}(200^2=160^2)\\\underline{A=11309.73 mm^2}\\ I=\frac{\pi}{64}(D^4-d^4)=\frac{\pi}{64}(200^4-160^4)=46.36\times10^6mm\\ z=\frac{I}{y}=\frac{46.36\times10^6}{100}=463.6\times10^3mm^3 $

Since the column is fixed at both ends

$ L_{eff}=L=6000mm\\ L_{eff}=\frac{L}{2}=3000mm$


$\underline{Extreme\ Stresses:}$

Maximum bending moment =

p.e. sec$\left( \frac{L}{2}\sqrt{\frac{P}{EI}}\right) $

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