and 5 others joined a min ago.
0
1.4kviews
Apply Cayley-Hamilton theorem for $A = \begin{bmatrix} \ 1 & 2 \\ \ 2 & -1 \\ \end{bmatrix}$ and deduce that $A^8=625I$
1 Answer
0
131views
written 2.3 years ago by
teamques10
★ 65k
|
• modified 2.3 years ago |
Given,
$A = \begin{bmatrix} \ 1 & 2 \\ \ 2 & -1 \\ \end{bmatrix}$
To Prove :- $A^8 = 625I$
Proof :-
$A = \begin{bmatrix} \ 1 & 2 \\ \ 2 & -1 \\ \end{bmatrix}$
The characteristic equation of A will be |A - λI| = 0
$\implies …
and 4 others joined a min ago.
ADD COMMENT
EDIT
Please log in to add an answer.