Solution :

$$ \begin{array}{l}\text { Let, } m=\frac{\Sigma f_{i} x_{i}}{\sum f_{i}}=\frac{(0 \times 123)+(1 \times 59)+(2 \times 14)+(3 \times 3)+(4 \times 1)}{123+59+14+3+1} \\ \therefore m=0.5 \text { and } N=200 \end{array} $$ By poisson distribution formulae, $$ \begin{array}{l} P(X=x)=\frac{e^{-m} m^{x}}{x !} \\ P(X=0)=\frac{e^{-m} m^{0}}{0 !}=e^{-0.5} \times 1=0.6065 \end{array} $$ Now, By …