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Find Drain current of $M_4$
written 6.0 years ago by | • modified 2.3 years ago |
Subject: CMOS VLSI Design
Topic: CMOS analog building blocks
Difficulty: Difficult
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written 6.0 years ago by | • modified 2.3 years ago |
Subject: CMOS VLSI Design
Topic: CMOS analog building blocks
Difficulty: Difficult
written 6.0 years ago by | • modified 6.0 years ago |
$I_D\ of\ M_4$
$I_{Ref}=I_{D_1}$
$I_{D_2}=I_{Ref}\frac{(\frac{W}{L})_2}{(\frac{W}{L})_1}\ (M_1\ \&\ M_2\ \to current\ mirror)$
Now, $I_{D_2}=I_{D_3}$
$\therefore I_{D_3}=I_{Ref}\frac{(\frac{W}{L})_2}{(\frac{W}{L})_1}$
And $I_{out}=I_{D_4}=I_{D_3}\frac{(\frac{W}{L})_4}{(\frac{W}{L})_3}\ (M_3\ \&\ M_4 \ forms\ \ current \ \ mirror)$
$\therefore I_{out}=I_{Ref}\frac{(\frac{W}{L})_2}{(\frac{W}{L})_1}\frac{(\frac{W}{L})_4}{(\frac{W}{L})_3}$