Subject: Structural Analysis II

Topic: Flexibility Method

Difficulty: Medium / High

Free Bending Moment:

For Span AB BM at $E=\frac{wab}{l}=\frac{80\times2\times4}{6}=106.67KN.m$

For Span BC BM at $F=\frac{wl^{2}}{8}=\frac{20\times5^{2}}{8}=62.5kN.m$

For Span CD BM at $G=\frac{wab}{l}=\frac{60\times3\times2}{5}=72kN.m$

Support B sinks by 5mm =0.005m=-0.005(Downward)

$E=2.1\times10^{5}N/mm^{2}$

=$2.1\times10^{5}\frac{N}{(10^{-3})^{2}m^{2}}$

$=2.1\times10^{5}\times10^{6}N/m^{2}$

$I=9300cm^{4}$

$=9300\times{(10^{-2}})^{4}m^{4}$

$9300\times10^{-8}m^{4}$

$E\times I=2.1\times{10^{5}}\times{10}^{6}\times9300\times10^{-8}$

$(N/m^{2}) \times (m^{4})$

$=19830\times10^{3}N/m^{2}$

$=19530kN/m^{2}$

2) Free bending moment diagram

3)Applying Three moment theorem

For …