Subject: Structural Analysis II

Topic: Flexibility Method

Difficulty: Medium / High

As a support is fixed support. Therefore we have to use an imaginary span near the fixed end as shown in fig

1) Free bending moment

For Span AB BM at C=$\frac{wL^{2}}{8}=\frac{5\times(4)^{2}}{8}=10kN.m$

2) Free Bending Moment diagram

3) Applying theorem of three moments or elapeyron's theorem

For Span $A^{1}-A-B$

$MA^{1}l_{1}+2M_{A}(l_{1}+l_{2})+M_{B}l_{2}+\frac{6A_{1}x_{1}}{l_{1}}+\frac{6A_{2}x_{2}}{l_{2}}=0$ …