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Analyze the beam in the fig by MDM. Draw BMD.
1 Answer
| written 7.3 years ago by | • modified 7.3 years ago |
1) Fixed end moments :
AB =>
$M_{ab} = \frac{-wab^2}{l^2} = \frac{-10*2*3^2}{5^2}$ = -7.2 KN.m
$M_{ba} = \frac{wba^2}{l^2} = \frac{10*3*2^2}{5^2}$ = 4.8 KN.m
BC =>
$M_{bc} = \frac{-wl}{8} = \frac{-12*6}{8}$ = -9 KN.m
$M_{cb} = \frac{wl}{8} = \frac{12*6}{8}$ = 9 KN.m
2) Stiffness (K) :
$K_{BA} = \frac{HEI}{l} = \frac{4EI}{5}$ …