**1 Answer**

written 6.1 years ago by | modified 6.0 years ago by |

Total closing error in latitude = ∑.northing - ∑.southing =230.192 – 221.637 = 8.56 = +8.56 (correction –ve)

Total closing error in departure = ∑easting - ∑.westing =291.74 – 292.414 = -0.67 = -0.67 (correction +ve)

By applying Bowditch rule for adjustment of correction

Correction of latitude = $\frac{\text{error in latitude ×length of that side}}{\text{perimeter of traverse}}$

Correction of departure = $\frac{\text{error in departure ×length of that side}}{\text{perimeter of traverse}}$

Perimeter of traverse = 792.93m

Correction of latitude-

Correction in line PQ = $\frac{8.56×78}{92.93}$ = 0.8420

Correction latitude of line PQ = 49.086 – 0.8420 = 48.2441

Correction in line QR = $\frac{8.56×203.10}{792.93}$ = 2.1925

Correction latitude of line QR = 45.11 – 2.1925= 42.9175

Correction in line RS = $\frac{8.56×149.01}{792.93}$ = 1.6086

Correction latitude of line RS = -145.287 – 1.6086= -146.8956

Correction in line PQ = $\frac{8.56×152.70}{792.93}$ = 1.6484

Correction latitude of line PQ = - 76.35 – 1.6484= - 77.9984

Correction in line PQ = $\frac{8.56×210.12}{92.93}$ = 2.2683

Correction latitude of line PQ = 135.996 – 2.2683= 132.7277

Correction in departure

Correction in line PQ = $\frac{0.67×78}{792.93}$ = 0.0659

Correction departure of line PQ = 60.617 – 0.0659= 60.6829

Correction in line QR = $\frac{0.67×78}{792.93}$ = 0.1716

Correction departure of line QR = 198.026 – 0.1716= 198.1976

Correction in line RS = $\frac{0.67×78}{92.93}$ = 0.1259

Correction departure of line RS = 33.097 – 0.1259= 33.2229

Correction in line SP = $\frac{0.67×78}{792.93}$ = 0.1290

Correction departure of line SP = -132.242 – 0.1290= -132.113

Correction in line TP = $\frac{0.67×78}{792.93}$ = 0.1775

Correction departure of line TP = -160.172 – 0.1775= -159.9945

Correct latitude and departure