Question: Difference between specific Gravity of solids(G) and specific gravity of soil
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modified 6 days ago by gravatar for Sanket Shingote Sanket Shingote ♦♦ 280 written 14 months ago by gravatar for stanzaa37 stanzaa3740
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1)Embankment:-

e=$\frac{n}{1-n}$=$\frac{0.3}{1-0.3}$=0.428

s=$\frac{w.G}{e}$ = $\frac{0.15 \times 2.68}{0.428}$

s= 93.9%

$\gamma=\frac{(G+s.e)}{(1+e)}\gamma w$

$[\frac{2.68 + 0.939 + 0.4278}{1+0.428}]\times 9.81$

=21.17 $kN/m^{3}$

$a_{c}=n(1-s)$

=0.3[1-0.939]

$a_{c}$=0.0183

wt of soil=$\gamma \times 2000m^{3}$

w=$17 \times 2000 kN$

Volume of compacted embankment

v=$\frac{w}{v}$ $\frac{17 \times 2000}{21.17} =1606m^{3}$

Volume of compacted embankment is $1606m^{3}$

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written 14 months ago by gravatar for stanzaa37 stanzaa3740
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