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Simplify the following
written 5.6 years ago by | • modified 3.4 years ago |
$AB+B+\overline{A}\overline{C}+A\overline{B}C(AB+C)AB+B+\overline{A}\overline{C}+A\overline{B}C(AB+C)$
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written 5.6 years ago by | • modified 3.4 years ago |
$AB+B+\overline{A}\overline{C}+A\overline{B}C(AB+C)AB+B+\overline{A}\overline{C}+A\overline{B}C(AB+C)$
written 5.6 years ago by |
$F = AB+B+\overline{A}\overline{C}+A\overline{B}C(AB+C)AB+B+\overline{A}\overline{C}+A\overline{B}C(AB+C)$ $\hspace{14cm}...(\overline{A}\overline{C}=\overline{A}+\overline{C})$ $= B+\overline{A}+\overline{C}+0+0+B+\overline{A}+\overline{C}+0+A\overline{B}C$ $\hspace{9.5cm}...(B+B) =B,(\overline{A}+\overline{A})=\overline{A},(\overline{C}+\overline{C})=\overline{C}$ $=B+\overline{A}+\overline{C}+A\overline{B}C$