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Design 4 bit ring counter using JK-FF draw the timing diagram for the same.

Subject: Logic Design

Topic: Sequential Logic Design

Difficulty: Medium

1 Answer
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• In a Johnson Ring Counter, the Q output of each stage of flip flop is connected to the D output of the next stage.

• And the compliment output of the last flip flop is connected to the back to the input of the first flip flop.

• Following figure shows the concept of Johnson ring counter.

enter image description here

• It is also called as Twisting Ring Counter or switch tail counter.

• Johnson counter can be implemented with SR or JK Flip Flop as well.

• As shown in figure feedback from almost rightmost flip-flop complement output to the leftmost flip-flop input.

• This arrangement produces a sequence of states

• Initially all the register is cleared so output of QA, Qb, QC and Qd are zero.

• The output of the last stage, Qd is zero. Therefore complement output of last stage, Qd is one

• These are connected to back to the D input of the first stage of Da is one.

• The first falling clock edge produces Qa=1 and Qb,Qc,and Qd are zero.

• The next clock pulse produces Qa=1 Qb=1 QC=0 and Qd=0.

• Sequence of stages are shown in following table

enter image description here

  1. Here 4 bit register is used so 4 bit sequence has a total of 8 sequences.
  2. Following figure shows timing sequence for four bit Johnson Counter.
  3. If we design a counter of five bit sequence, it has total ten states.
  4. An n-stage Johnson Counter will produce a modulus of 2*n ‘(stage=n) where n is the number of stages in flip-flop

enter image description here

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