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A quartz crystal of thickness 1.5mm vibrating with resonance.

written 7.2 years ago by teamques10 ★ 70k

•   modified 5.6 years ago

Calculate it’s fundamental frequency if the Young’s modulus of quartz crystal is $7.9×10^{10}N/m^2 $and density is 2650 kg/$m^3$ .

engineering physics

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written 7.2 years ago by teamques10 ★ 70k

Given Data :- t_1 = 1mm = $10^{(-3)}mm \hspace{1cm} Y = 7.9 × 10^{10}N/m^2$

$ρ = 2650 kg/m^3$

Calculations :- $f = \frac{1}{2 × 10^{(-3)}} \sqrt{\frac{7.9 ×10^10}{2650}} = 2.73 MHz $

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