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Find the minimum energy of neutron confined to a nucleus of size of the order of (10)^{-14} m.
written 7.2 years ago by gravatar for teamques10 teamques10 ★ 70k •   modified 5.6 years ago

Given mass of neutron =$ 1.675×10^{(-27)}$ kg
engineering physics
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written 7.2 years ago by gravatar for teamques10 teamques10 ★ 70k

Given data :- L = $10^{(-14)}$ m

$ Formula :- E_n= n^2 (h^2/(8mL^2 )) …………………….(n = 1,2,3…..)$

$ Solution :- E_n= n^{2} (h^2/(8mL^2 )) = ((6.63 × 10^{(-34)})×(6.63 × 10^{(-34)}))/(8×1.67 ×10^{(-27)}×{(10^{(-14)})}^2 ) …..(n=1)$

$ E_1 = 3.29 × 10^{(-13)}J$

Lower energy$ = 3.29 × 10^{(-13)}J$

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