Find the minimum energy of neutron confined to a nucleus of size of the order of (10)^{-14} m.

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written 7.6 years ago by

teamques10 ★ 70k

• modified 6.0 years ago

Given mass of neutron =$ 1.675×10^{(-27)}$ kg

engineering physics

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1.6kviews

written 7.6 years ago by

teamques10 ★ 70k

Given data :- L = $10^{(-14)}$ m

$ Formula :- E_n= n^2 (h^2/(8mL^2 )) …………………….(n = 1,2,3…..)$

$ Solution :- E_n= n^{2} (h^2/(8mL^2 )) = ((6.63 × 10^{(-34)})×(6.63 × 10^{(-34)}))/(8×1.67 ×10^{(-27)}×{(10^{(-14)})}^2 ) …..(n=1)$

$ E_1 = 3.29 × 10^{(-13)}J$

Lower energy$ = 3.29 × 10^{(-13)}J$

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