if the Hall coefficient of the sample is $2.25× 10^{-5} m^3/C$. And the mobility of holes is $0.025m^2/V-sec$

Given Data :- $μ_h = 0.025m^2/V-sec \hspace{1cm} R_H = 2.25× 10^{(-5)} m^3/C$

Formula :- $ ρ= 1/σ ,\hspace{1cm} μ_h= σR_H$

Calculations :- $ σ= μ_H/R_H = 0.025/(2.25×10^{(-5)} ) = 1111.11 mho/m$

$ρ=9×10^{(-4)} Ω-m$

Answer :- Resistivity = $9×10^{(-4)}$ Ω-m